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253 LearnersLast updated on August 5, 2025

The square root is the inverse of the square of the number. 233 is not a perfect square. The square root of 233 is expressed in both radical and exponential forms. In the radical form, it is expressed as √233, whereas (233)^(1/2) in the exponential form. √233 ≈ 15.2643, which is an irrational number because it cannot be expressed in the form of p/q, where p and q are integers and q ≠ 0.
The prime factorization method is used for perfect square numbers. However, the prime factorization method is not used for non-perfect square numbers where the long-division method and approximation method are used. Let us now learn the following methods:
The product of prime factors is the prime factorization of a number. Now let us look at how 233 is broken down into its prime factors.
Step 1: Finding the prime factors of 233 233 is a prime number, so it cannot be broken down into smaller prime factors.
Step 2: Since 233 is a prime number and not a perfect square, calculating the square root using prime factorization is impossible.


The long division method is particularly used for non-perfect square numbers. Let us now learn how to find the square root using the long division method, step by step.
Step 1: Group the numbers from right to left. In the case of 233, we need to group it as 33 and 2.
Step 2: Find n whose square is less than or equal to 2. We can say n is ‘1’ because 1 x 1 is less than or equal to 2. Now the quotient is 1, and after subtracting 1 from 2, the remainder is 1.
Step 3: Bring down 33, which is the new dividend. Add the old divisor (1) to itself, which gives us 2 as the new divisor.
Step 4: Use 2 as the new divisor to find a value of n such that 2n x n ≤ 133. Let us consider n as 5, now 25 x 5 = 125.
Step 5: Subtract 125 from 133, the difference is 8.
Step 6: Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 800.
Step 7: Find the new divisor, which is 105 because 1050 x 5 = 525.
Step 8: Subtracting 525 from 800 gives us the result 275.
Step 9: Continue doing these steps until we get two numbers after the decimal point. So the square root of √233 is approximately 15.26.
The approximation method is another method for finding square roots. It is an easy method to find the square root of a given number. Now let us learn how to find the square root of 233 using the approximation method.
Step 1: Find the closest perfect square of √233. The smallest perfect square less than 233 is 225, and the largest perfect square greater than 233 is 256. √233 falls somewhere between 15 and 16.
Step 2: Apply the formula (Given number - smallest perfect square) / (Greater perfect square - smallest perfect square). Using the formula (233 - 225) / (256 - 225) = 0.258. Adding the integer part to the decimal, 15 + 0.258 ≈ 15.26.
Students often make mistakes while finding the square root, such as forgetting about the negative square root or skipping the long division method. Let us look at a few common mistakes in detail.
Can you help Max find the area of a square box if its side length is given as √233?
The area of the square is 233 square units.
The area of the square = side².
The side length is given as √233.
Area of the square = side² = √233 x √233 = 233.
Therefore, the area of the square box is 233 square units.
A square-shaped building measuring 233 square feet is built; if each of the sides is √233, what will be the square feet of half of the building?
116.5 square feet
We can divide the given area by 2 as the building is square-shaped.
Dividing 233 by 2 gives us 116.5.
So half of the building measures 116.5 square feet.
Calculate √233 x 5.
76.32
The first step is to find the square root of 233, which is approximately 15.26.
The second step is to multiply 15.26 by 5.
So 15.26 x 5 = 76.32.
What will be the square root of (225 + 8)?
The square root is approximately 15.26.
To find the square root, we need to find the sum of (225 + 8).
225 + 8 = 233, and then √233 ≈ 15.26.
Therefore, the square root of (225 + 8) is approximately ±15.26.
Find the perimeter of the rectangle if its length 'l' is √233 units and the width 'w' is 38 units.
We find the perimeter of the rectangle as approximately 106.52 units.
Perimeter of the rectangle = 2 × (length + width).
Perimeter = 2 × (√233 + 38)
= 2 × (15.26 + 38)
= 2 × 53.26
= 106.52 units.

Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
: He loves to play the quiz with kids through algebra to make kids love it.






