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693 LearnersLast updated on August 5, 2025

The cube root of 128 is 5.03968419958. The cube root of 128 is expressed as ∛128 in radical form, where the “∛" sign is called the “radical” sign.
In exponential form, it is written as (128)⅓. If “m” is the cube root of 128, then, m3=128. Let us find the value of “m”.
The cube root of 128 is expressed as 4∛2 as its simplest radical form,
since 128 = 2×2×2×2×2×2×2
∛128 = ∛(2×2×2×2×2×2×2)
Group together three same factors at a time and put the remaining factor under the ∛ .
∛128= 4∛2
We can find cube root of 128 through a method, named as, Halley’s Method. Let us see how it finds the result.
Now, what is Halley’s Method? It is an iterative method for finding cube roots of a given number N, such that, x3=N, where this method approximates the value of “x”.
Formula is ∛a≅ x((x3+2a) / (2x3+a)), where
a=given number whose cube root you are going to find.
x=integer guess for the cubic root
Let us apply Halley’s method on the given number 128.
Step 1: Let a=128. Let us take x as 5, since, 53=125 is the nearest perfect cube which is less than 128.
Step 2: Apply the formula. ∛128≅ 5((53+2×128) / (2(5)3+128))= 5.039…
Hence, 5.039… is the approximate cubic root of 128.


some common mistakes and their solutions are given below:
Find (∛128/ ∛64) × (∛128/ ∛64) × (∛128/ ∛64)
(∛128/ ∛64) × (∛128/ ∛64) × (∛128/ ∛64)
= (∛128× ∛128× ∛128) / (∛64× ∛64× ∛64)
=((128)⅓)3/ ((64)⅓)3
=128/64
= 2
Answer: 2
We solved and simplified the exponent part first using the fact that, ∛128=(128)⅓ and ∛64=(64)⅓ , then solved.
If y = ∛128, find y^3.
y=∛128
⇒ y3= (∛128)3
⇒ y3= 128
Answer: 128
(∛128)3=(1281/3)3=128.
Using this, we found the value of y3.
Subtract ∛128 - ∛125
∛128-∛125
= 5.039–5
= 0.039
Answer: 0.039
We know that the cubic root of 125 is 5, hence subtracting ∛125 from ∛128.
What is ∛(128^6) ) ?
∛(1286)
= ((128)6))1/3
=( 128)2
= 16384
Answer: 16384
We solved and simplified the exponent part first using the fact that, ∛128=(128)⅓, then solved.
Find ∛(128+(-3))
∛(128-3)
= ∛125
= 5
Answer: 5
Simplified the expression, and found out the cubic root of the result.

Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
: He loves to play the quiz with kids through algebra to make kids love it.






