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855 LearnersLast updated on August 5, 2025

The cube root of 16 is 2.51984209979. The cube root of 16 is expressed as ∛16 in radical form, where the “ ∛ ” sign is called the “radical” sign. In exponential form, it is written as (16)⅓. If “m” is the cube root of 16, then, m3=16. Let us find the value of “m”.
The cube root of 16 is expressed as 2∛2 as its simplest radical form,
since 16 = 2×2×2×2
∛16 = ∛(2×2×2×2)
Group together three same factors at a time and put the remaining factor under the ∛ .
∛16= 2∛2
We can find cube root of 16 through a method, named as, Halley’s Method. Let us see how it finds the result.
Now, what is Halley’s Method? It is an iterative method for finding cube roots of a given number N, such that, x3=N, where this method approximates the value of “x”.
Formula is ∛a≅ x((x3+2a) / (2x3+a)), where
a=given number whose cube root you are going to find
x=integer guess for the cubic root
Let us apply Halley’s method on the given number 16.
Step 1: Let a=16. Let us take x as 2, since, 23=8 is the nearest perfect cube which is less than 16.
Step 2: Apply the formula. ∛16≅ 2((23+2×16) / (2(2)3+16))= 2.5
Hence, 2.5 is the approximate cubic root of 16.


here's some common mistakes with their solutions given below:
Find (∛32/ ∛16) × (∛32/ ∛16) × (∛32/ ∛16)
(∛32/ ∛16) × (∛32/ ∛16) × (∛32/ ∛16)
= (∛32× ∛32× ∛32) / (∛16× ∛16× ∛16)
= ((32)⅓)3/ ((16)⅓)3
= 32/16
= 2
Answer: 2
We solved and simplified the exponent part first using the fact that, ∛32=(32)⅓ and ∛16=(16)⅓ , then solved.
If y = ∛16, find y^3/ y^6
y=∛16
⇒ y3/y6= (∛16)3 / (∛16)6
⇒ y3/y6
= 16/ (16)2
= 1/16
Answer: 1/16
(∛16)3=(161/3)3=16, and ∛16)6=(161/3)6=(16)2. Using this, we found the value of y3/y6.
Multiply ∛16 × ∛64
∛16×∛64
= 2.519×4
= 10.076
Answer: 10.076
We know that the cubic root of 64 is 4, hence multiplying ∛64 with ∛16.
What is ∛(16⁶) ?
∛(166)
= ((16)6))1/3
=( 16)2
= 256
Answer: 256
We solved and simplified the exponent part first using the fact that, ∛16=(16)⅓, then solved.
Find ∛(16+(-8)).
∛(16-8)
= ∛8
= 2
Answer: 2
Simplified the expression, and found out the cube root of the result.

Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
: He loves to play the quiz with kids through algebra to make kids love it.






