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592 LearnersLast updated on August 5, 2025

The cube root of 75 is 4.21716332651. The cube root of 75 is expressed as ∛75 in radical form, where the “∛" sign is called the “radical” sign. In exponential form, it is written as (75)⅓. If “m” is the cube root of 75, then, m3=75. Let us find the value of “m”.
The cube root of 75 is expressed as ∛75 as its simplest radical form,
since 75 = 5×5×3
∛75 = ∛(5×5×3)
Group together three same factors at a time and put the remaining factor under the ∛ .
∛75= ∛75
We can find cube root of 75 through a method, named as, Halley’s Method. Let us see how it finds the result.
Now, what is Halley’s Method? It is an iterative method for finding cube roots of a given number N, such that, x3=N,
where this method approximates the value of “x”.
Formula is ∛a≅ x((x3+2a) / (2x3+a)), where
a=given number whose cube root you are going to find
x=integer guess for the cubic root
Let us apply Halley’s method on the given number 75.
Step 1: Let a=75. Let us take x as 4, since, 43=64 is the nearest perfect cube which is less than 75.
Step 2: Apply the formula. ∛75≅ 4((43+2×75) / (2(4)3+75))= 4.12…
Hence, 4.12… is the approximate cubic root of 75.


Here are some common mistakes with their solutions given:
Find (∛75/ ∛64) × (∛75/ ∛64) × (∛75/ ∛64)
(∛75/ ∛64) × (∛75/ ∛64) × (∛75/ ∛64)
= (∛75× ∛75× ∛75) / (∛64× ∛64× ∛64)
=((75)⅓)3/ ((64)⅓)3
=75/64
Answer: 75/64
We solved and simplified the exponent part first using the fact that, ∛75=(75)⅓ and ∛64=(64)⅓ , then solved.
If y = ∛75, find y³.
y=∛75
⇒ y3= (∛75)3
⇒ y3= 75
Answer: 75
(∛75)3=(751/3)3=75. Using this, we found the value of y3.
Subtract ∛75 - ∛64
∛75-∛64
= 4.217–4
= 0.217
Answer: 0.217
We know that the cubic root of 64 is 4, hence subtracting ∛64 from ∛75.
What is ∛(75⁶) ?
∛(756)
= ((75)6))1/3
=( 75)2
= 5625
Answer: 5625
We solved and simplified the exponent part first using the fact that, ∛75=(75)⅓, then solved.
Find ∛(75+(-11)).
∛(75-11)
= ∛64
= 4
Answer: 4
Simplified the expression, and found out the cubic root of the result.

Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
: He loves to play the quiz with kids through algebra to make kids love it.






